**Logical Reasoning Questions are an inseparable part of IBPS PO, IBPS Clerk, SBI PO, SBI Clerk, SSC CGL, SSC CHSL and other competitive exams, therefore as an aspirant for these jobs, it becomes almost mandatory for you to get command over this topic. **

Logical reasoning questions from logical series are not only fun and challenging but also an integral part IBPS PO, IBPS Clerk, SBI PO, SBI Clerk, SSC CGL, SSC CHSL and other competitive exams. With a little practice and knowledge of few hacks, logical reasoning questions can be solved in just a few seconds! They are pretty much capable of making a difference to your score and taking you through the cut-off. In a two series blog post on logical reasoning questions, we will discuss logical reasoning questions that are based on mathematical operators and those reasoning questions that are based on number series.

Before we start discussing logical reasoning questions based on mathematical operators, you must go through the 5 tricks that will help you maximize your score in the logical reasoning section.

**Set I – Mathematical Operations Logical Reasoning Questions**

Of the various kind of logical reasoning questions asked in IBPS PO, SBI PO and SSC CGL, the most commonly asked ones are about mathematical operations. Such logical reasoning questions need you to perform various mathematical operations based on the conditions specified to get to the answer.

**Problem 1**

**:**If A is followed by B then C-

**Question 1:**

If P is the resultant of the first row, what will be the resultant of the second row?

**Solution 1:**

Based on the 5 conditions that have been given, we have to find the resultant of the 2nd row. To find the resultant of the 2nd row, we first have to find the value of P, which is the resultant of the 1st row. To find the resultant of the 1st row, we have to do nothing but simply follow the conditions and perform the required mathematical operations.

Let us start with the first two numbers- 15 and 8

15 is an odd number, so we refer to conditions (i), (iv) and (v), since 8 is an even number we will refer to condition (v).

So we need to subtract 8 from 15-

15 – 8 = 7

Now the next pair of number we have to deal with are- 7 and 21

7 is an odd number, so we refer to conditions (i), (iv) and (v), as 21 is a composite odd number we will refer to condition (i).

So we need to add 21 to 7-

7 + 21 = 28

28 is the resultant of the first row and the value of P.

Now we move to the 2nd row with the value of P as 28.

28 is an even number, so we refer to conditions (ii) and (iii), since 3 is an odd number we will refer to condition (ii).

So we need to add 28 to 3-

28 + 3 = 31

Moving on to the next pair of numbers- 31 and 27

31 is an odd number, so we go back to conditions (i), (iv) and (v), since 27 is an odd number we will refer to condition (i).

So we need to add 31 to 27-

31 + 27 = 58

Therefore, the answer, the resultant of the 2nd row is 58.

This how logical reasoning questions can be easily solved by just following the steps.

**Question 2:**

If r is the resultant of the first row, what will be the resultant of the second row?

**Solution 2:**

Based on the 5 conditions that have been given, we have to find the resultant of the 2nd row. To do that we first have to find the value of r, this is nothing but the resultant of the 1st row.

Starting with the first two numbers- 85 and 17

85 is an odd number, so we refer to conditions (i), (iv) and (v), since 17 is an odd prime number we will refer to condition (iv).

So we need to divide 85 to 17-

85 + 17 = 5

Now the next pair of numbers we have to deal with are- 5 and 35

Once again 5 is an odd number, so we refer to conditions (i), (iv) and (v), since 35 is a composite odd number we will refer to condition (i).

So we need to add 5 and 35-

5 + 35 = 40

Since 40 is the resultant of the 1st row, it will also be the value of r.

Now the next pair of numbers is- 19 and 16

As 16 is an even number, we have to use the (ii) and (iii) condition; also since 19 is an odd number, the condition we have to refer to here is (ii).

So we need to add 16 and 19-

16 + 19 = 35

The next pair of numbers is – 35 and 40

35 is an odd number, we have to use the so we refer to conditions (i), (iv) and (v), since 40 is an even number we will refer to condition (v).

So we need to subtract 40 from 35-

35 – 40 = -5

Hence, the answer is -5.

**Logical Reasoning Questions for Practice**

Directions (1-2): In each of the following questions, two rows of numbers are given. The resultant numbers are given. The resultant number in each row is to be worked out separately based on the following rules and the questions below the rows of numbers are to be answered. The operations of numbers progress from the left to right.

Rules:

i) If an odd number is followed by another composite odd number, they are to be added

ii) If an even number is followed by an odd number they are to be added.

iii) If an even number is followed by a number which is the perfect square, the even number is to be subtracted from the perfect square.

iv) If an odd number is followed by a prime odd number the first number is to be divided by the second number.

v) If an odd number is followed by an even number, the second one is to be subtracted from the first number.

Question 1: 15 8 21

P 3 27

If ‘P’ is the resultant of the first row, what will be the resultant of second row?

P 3 27

If ‘P’ is the resultant of the first row, what will be the resultant of second row?

1) 58 2) 76 3) 27 4) 82 5) None of these

Question 2: 12 64 17

20 m 16

If ‘m’ is the resultant of the first row, what will be the resultant of the second row?

20 m 16

If ‘m’ is the resultant of the first row, what will be the resultant of the second row?

1) 69 2) 85 3) 101 4) 121 5) None of these

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